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Suppose that a specification calls for LTL = 1.8 and UTL = 6.4. A sample of 100 parts found [tex]\mu = 4.2[/tex] and [tex]\sigma = 0.6[/tex]. Compute [tex]Cp[/tex], [tex]Cpl[/tex], [tex]Cpu[/tex], and [tex]Cpk[/tex]. Do not round intermediate calculations. Round your answers to three decimal places.

- [tex]Cp:[/tex]
- [tex]Cpl:[/tex]
- [tex]Cpu:[/tex]
- [tex]Cpk:[/tex]

Answer :

To calculate Cp, Cpl, Cpu, and Cpk, we need to use the given data. By plugging the given values into the formulas, we can calculate Cp, Cpl, Cpu, and Cpk.

Cp measures the process capability by comparing the specification limits with the natural variation of the process. It gives an indication of how well the process meets the specifications. Cpl and Cpu, on the other hand, measure the process capability on the lower and upper specification limits, respectively. Finally, Cpk is a measure that takes into account both the lower and upper specification limits, giving a more comprehensive view of the process capability.


Calculate Cp:
Cp measures the process capability and is determined using the formula:

Cp = (UTL - LTL) / (6 * σ)

In this case, UTL = 6.4, LTL = 1.8, and σ = 0.6. Plugging these values into the formula, we get:

Cp = (6.4 - 1.8) / (6 * 0.6) = 4.6 / 3.6 = 1.278

So, the Cp is 1.278.

Calculate Cpl:
Cpl measures the process capability on the lower specification limit and is determined using the formula:

Cpl = (μ - LTL) / (3 * σ)

In this case, μ = 4.2, LTL = 1.8, and σ = 0.6. Plugging these values into the formula, we get:

Cpl = (4.2 - 1.8) / (3 * 0.6) = 2.4 / 1.8 = 1.333

So, the Cpl is 1.333.

Calculate Cpu:
Cpu measures the process capability on the upper specification limit and is determined using the formula:

Cpu = (UTL - μ) / (3 * σ)

In this case, UTL = 6.4, μ = 4.2, and σ = 0.6. Plugging these values into the formula, we get:

Cpu = (6.4 - 4.2) / (3 * 0.6) = 2.2 / 1.8 = 1.222

So, the Cpu is 1.222.

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