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Given [tex]f(x) = 5^2x[/tex], evaluate [tex]f(-1)[/tex], [tex]f(0)[/tex], and [tex]f(2)[/tex].

A. [tex]\frac{1}{25}, 0, 625[/tex]
B. [tex]25, 1, -25[/tex]
C. [tex]\frac{1}{25}, 0, 25[/tex]
D. [tex]\frac{1}{25}, 1, 625[/tex]

Answer :

The value of the function at f(–1), f(0), and f(2) will be 1/25, 1, 625 thus option (d) is correct.

What is a function?

A certain kind of relationship called a function binds inputs to essentially one output.

In other words, the function is a relationship between variables, and the nature of the relationship defines the function for example y = sinx and y = x +6 like that.

As per the given function,

f(x) = [tex]5^{2x}[/tex]

Put x = -1

f(-1) = 5⁻² = 1/5² = 1/625

Put x = 0

f(0) = 5⁰ = 1

Put x = 2

f(2) = 5²ˣ² = 5⁴ = 625

Hence "The function's value at f(-1), f(0), and f(2) is 1/25, 1, 625".

For more about the function,

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Rewritten by : Batagu

Answer:

1/25, 1, 625

Step-by-step explanation: