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Write the exponential equation in logarithmic form.

[tex]\[\frac{1}{25}=5^{-2}\][/tex]

[tex]\[\log_{5} \frac{1}{25} = -2\][/tex]

Answer :

We start with the exponential equation

[tex]$$
\frac{1}{25} = 5^{-2}.
$$[/tex]

Recall that the relationship between exponential and logarithmic forms is given by

[tex]$$
b^y = x \quad \Longleftrightarrow \quad \log_b(x) = y.
$$[/tex]

In our equation, the base is [tex]$5$[/tex], the exponent is [tex]$-2$[/tex], and the value is [tex]$\frac{1}{25}$[/tex]. Therefore, rewriting the equation in logarithmic form gives

[tex]$$
\log_{5}\left(\frac{1}{25}\right) = -2.
$$[/tex]

This is the logarithmic form of the given equation.

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