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Answer :
We start with the exponential equation
[tex]$$
\frac{1}{25} = 5^{-2}.
$$[/tex]
Recall that the relationship between exponential and logarithmic forms is given by
[tex]$$
b^y = x \quad \Longleftrightarrow \quad \log_b(x) = y.
$$[/tex]
In our equation, the base is [tex]$5$[/tex], the exponent is [tex]$-2$[/tex], and the value is [tex]$\frac{1}{25}$[/tex]. Therefore, rewriting the equation in logarithmic form gives
[tex]$$
\log_{5}\left(\frac{1}{25}\right) = -2.
$$[/tex]
This is the logarithmic form of the given equation.
[tex]$$
\frac{1}{25} = 5^{-2}.
$$[/tex]
Recall that the relationship between exponential and logarithmic forms is given by
[tex]$$
b^y = x \quad \Longleftrightarrow \quad \log_b(x) = y.
$$[/tex]
In our equation, the base is [tex]$5$[/tex], the exponent is [tex]$-2$[/tex], and the value is [tex]$\frac{1}{25}$[/tex]. Therefore, rewriting the equation in logarithmic form gives
[tex]$$
\log_{5}\left(\frac{1}{25}\right) = -2.
$$[/tex]
This is the logarithmic form of the given equation.
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