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Rewrite [tex]$5^{-2}=\frac{1}{25}$[/tex] in logarithmic form. Write any fractions in your equation in simplest form.

[tex]\log_{5}\left(\frac{1}{25}\right) = -2[/tex]

Answer :

To rewrite the equation [tex]\(5^{-2} = \frac{1}{25}\)[/tex] in logarithmic form, let's follow these steps:

1. Understand the Components:
- The original equation is in exponential form, where the base is 5, the exponent is -2, and the result is [tex]\(\frac{1}{25}\)[/tex].

2. Identify the Parts for Logarithmic Form:
- Logarithmic form can be written as [tex]\(\log_{\text{base}}(\text{result}) = \text{exponent}\)[/tex].

3. Apply the Components:
- Here, the base is 5.
- The result is [tex]\(\frac{1}{25}\)[/tex].
- The exponent is -2.

4. Write the Logarithmic Equation:
- Based on the identified parts, we can write the logarithmic form of the given exponential equation as:
[tex]\[
\log_5{\frac{1}{25}} = -2
\][/tex]

This equation shows that the logarithm of [tex]\(\frac{1}{25}\)[/tex] with base 5 is equal to -2.

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Rewritten by : Batagu