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what is the expected value for an expirement with the following outcomes and corresponding probabilities (3)/(25)(5)/(25)(6)/(25)(5)/(25)(3)/(25)(1)/(25)(1)/(25)(1)/(25)

Answer :

The expected value for the given outcomes and probabilities is (9/25) + (25/25) + (36/25) + (1/25)

The expected value is a measure of the average outcome for a random experiment. To find the expected value, you multiply each outcome by its corresponding probability and add up the products.

In this case, we have the outcomes 3, 5, 6, and 1, with corresponding probabilities of 3/25, 5/25, 6/25, and 1/25, respectively. To find the expected value, you multiply each outcome by its probability and add the products together:

  • (3/25) * 3
  • (5/25) * 5
  • (6/25) * 6
  • (1/25) * 1

Simplifying these products and adding them up, the expected value is (9/25) + (25/25) + (36/25) + (1/25).

To know more about probabilities refer here:

https://brainly.com/question/29574962

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